Base | Representation |
---|---|
bin | 101100011011100001101… |
… | …111010000100101010001 |
3 | 101210212212201212201110012 |
4 | 230123201233100211101 |
5 | 400010440243324244 |
6 | 10254343245044305 |
7 | 433405330104014 |
oct | 54334157204521 |
9 | 11725781781405 |
10 | 3053214042449 |
11 | a7795180345a |
12 | 413897256695 |
13 | 191bbc416c9c |
14 | a7ac242937b |
15 | 5464b35c89e |
hex | 2c6e1bd0951 |
3053214042449 has 2 divisors, whose sum is σ = 3053214042450. Its totient is φ = 3053214042448.
The previous prime is 3053214042401. The next prime is 3053214042451. The reversal of 3053214042449 is 9442404123503.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2378750982400 + 674463060049 = 1542320^2 + 821257^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3053214042449 is a prime.
Together with 3053214042451, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (3053214042469) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1526607021224 + 1526607021225.
It is an arithmetic number, because the mean of its divisors is an integer number (1526607021225).
Almost surely, 23053214042449 is an apocalyptic number.
It is an amenable number.
3053214042449 is a deficient number, since it is larger than the sum of its proper divisors (1).
3053214042449 is an equidigital number, since it uses as much as digits as its factorization.
3053214042449 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 414720, while the sum is 41.
The spelling of 3053214042449 in words is "three trillion, fifty-three billion, two hundred fourteen million, forty-two thousand, four hundred forty-nine".
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