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3053465650097 is a prime number
BaseRepresentation
bin101100011011110000101…
…111000100001110110001
3101210220112021022201020222
4230123300233010032301
5400011444201300342
610254424233542425
7433414503533012
oct54336057041661
911726467281228
103053465650097
11a77a70834a65
12413947574a15
13191c2c5a0355
14a7b07a03009
15546634aced2
hex2c6f0bc43b1

3053465650097 has 2 divisors, whose sum is σ = 3053465650098. Its totient is φ = 3053465650096.

The previous prime is 3053465650091. The next prime is 3053465650141. The reversal of 3053465650097 is 7900565643503.

3053465650097 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1695644104561 + 1357821545536 = 1302169^2 + 1165256^2 .

It is a cyclic number.

It is not a de Polignac number, because 3053465650097 - 230 = 3052391908273 is a prime.

It is a super-2 number, since 2×30534656500972 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (3053465650091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1526732825048 + 1526732825049.

It is an arithmetic number, because the mean of its divisors is an integer number (1526732825049).

Almost surely, 23053465650097 is an apocalyptic number.

It is an amenable number.

3053465650097 is a deficient number, since it is larger than the sum of its proper divisors (1).

3053465650097 is an equidigital number, since it uses as much as digits as its factorization.

3053465650097 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10206000, while the sum is 53.

The spelling of 3053465650097 in words is "three trillion, fifty-three billion, four hundred sixty-five million, six hundred fifty thousand, ninety-seven".