Base | Representation |
---|---|
bin | 101100011011110001010… |
… | …100001001110000010001 |
3 | 101210220112221121122021021 |
4 | 230123301110021300101 |
5 | 400012004143401144 |
6 | 10254425222155441 |
7 | 433414652263624 |
oct | 54336124116021 |
9 | 11726487548237 |
10 | 3053475372049 |
11 | a77a76275233 |
12 | 41394a882b81 |
13 | 191c315c549b |
14 | a7b09013dbb |
15 | 5466427d884 |
hex | 2c6f1509c11 |
3053475372049 has 2 divisors, whose sum is σ = 3053475372050. Its totient is φ = 3053475372048.
The previous prime is 3053475372041. The next prime is 3053475372083. The reversal of 3053475372049 is 9402735743503.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2553626372049 + 499849000000 = 1598007^2 + 707000^2 .
It is a cyclic number.
It is not a de Polignac number, because 3053475372049 - 23 = 3053475372041 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3053475371987 and 3053475372005.
It is not a weakly prime, because it can be changed into another prime (3053475372041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1526737686024 + 1526737686025.
It is an arithmetic number, because the mean of its divisors is an integer number (1526737686025).
Almost surely, 23053475372049 is an apocalyptic number.
It is an amenable number.
3053475372049 is a deficient number, since it is larger than the sum of its proper divisors (1).
3053475372049 is an equidigital number, since it uses as much as digits as its factorization.
3053475372049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9525600, while the sum is 52.
The spelling of 3053475372049 in words is "three trillion, fifty-three billion, four hundred seventy-five million, three hundred seventy-two thousand, forty-nine".
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