Base | Representation |
---|---|
bin | 101100011011110001010… |
… | …100001001110000110011 |
3 | 101210220112221121122022112 |
4 | 230123301110021300303 |
5 | 400012004143401313 |
6 | 10254425222155535 |
7 | 433414652264003 |
oct | 54336124116063 |
9 | 11726487548275 |
10 | 3053475372083 |
11 | a77a76275264 |
12 | 41394a882bab |
13 | 191c315c54c6 |
14 | a7b09014003 |
15 | 5466427d8a8 |
hex | 2c6f1509c33 |
3053475372083 has 2 divisors, whose sum is σ = 3053475372084. Its totient is φ = 3053475372082.
The previous prime is 3053475372049. The next prime is 3053475372089. The reversal of 3053475372083 is 3802735743503.
It is a strong prime.
It is an emirp because it is prime and its reverse (3802735743503) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3053475372083 - 210 = 3053475371059 is a prime.
It is not a weakly prime, because it can be changed into another prime (3053475372089) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1526737686041 + 1526737686042.
It is an arithmetic number, because the mean of its divisors is an integer number (1526737686042).
Almost surely, 23053475372083 is an apocalyptic number.
3053475372083 is a deficient number, since it is larger than the sum of its proper divisors (1).
3053475372083 is an equidigital number, since it uses as much as digits as its factorization.
3053475372083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6350400, while the sum is 50.
The spelling of 3053475372083 in words is "three trillion, fifty-three billion, four hundred seventy-five million, three hundred seventy-two thousand, eighty-three".
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