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30535414134341 is a prime number
BaseRepresentation
bin1101111000101100101001…
…00000110011011001000101
311000010011020111211220011212
412330112110200303121011
513000243012004244331
6144535435310141205
76301053012422624
oct674262440633105
9130104214756155
1030535414134341
119802aa6249876
123511b744b1805
1314066285308ac
14777cc9abd6bb
1537e4699e3d2b
hex1bc594833645

30535414134341 has 2 divisors, whose sum is σ = 30535414134342. Its totient is φ = 30535414134340.

The previous prime is 30535414134307. The next prime is 30535414134347. The reversal of 30535414134341 is 14343141453503.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 16582731396100 + 13952682738241 = 4072190^2 + 3735329^2 .

It is an emirp because it is prime and its reverse (14343141453503) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-30535414134341 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (30535414134347) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15267707067170 + 15267707067171.

It is an arithmetic number, because the mean of its divisors is an integer number (15267707067171).

Almost surely, 230535414134341 is an apocalyptic number.

It is an amenable number.

30535414134341 is a deficient number, since it is larger than the sum of its proper divisors (1).

30535414134341 is an equidigital number, since it uses as much as digits as its factorization.

30535414134341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 518400, while the sum is 41.

Adding to 30535414134341 its reverse (14343141453503), we get a palindrome (44878555587844).

The spelling of 30535414134341 in words is "thirty trillion, five hundred thirty-five billion, four hundred fourteen million, one hundred thirty-four thousand, three hundred forty-one".