Base | Representation |
---|---|
bin | 1011011000001000… |
… | …1000110000000001 |
3 | 21212211122221211221 |
4 | 2312002020300001 |
5 | 22223311412231 |
6 | 1223014035041 |
7 | 135452454163 |
oct | 26602106001 |
9 | 7784587757 |
10 | 3054013441 |
11 | 1327a02556 |
12 | 712948a81 |
13 | 39894665b |
14 | 20d866933 |
15 | 12d1b2d11 |
hex | b6088c01 |
3054013441 has 2 divisors, whose sum is σ = 3054013442. Its totient is φ = 3054013440.
The previous prime is 3054013429. The next prime is 3054013463. The reversal of 3054013441 is 1443104503.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2959360000 + 94653441 = 54400^2 + 9729^2 .
It is an emirp because it is prime and its reverse (1443104503) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3054013441 is a prime.
It is not a weakly prime, because it can be changed into another prime (3054013421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1527006720 + 1527006721.
It is an arithmetic number, because the mean of its divisors is an integer number (1527006721).
Almost surely, 23054013441 is an apocalyptic number.
It is an amenable number.
3054013441 is a deficient number, since it is larger than the sum of its proper divisors (1).
3054013441 is an equidigital number, since it uses as much as digits as its factorization.
3054013441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 25.
The square root of 3054013441 is about 55263.1291278371. The cubic root of 3054013441 is about 1450.8537882562.
Adding to 3054013441 its reverse (1443104503), we get a palindrome (4497117944).
The spelling of 3054013441 in words is "three billion, fifty-four million, thirteen thousand, four hundred forty-one".
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