Base | Representation |
---|---|
bin | 101100011100011110111… |
… | …110101011011011011111 |
3 | 101210222112100012201001011 |
4 | 230130132332223123133 |
5 | 400020041310313001 |
6 | 10255033231000051 |
7 | 433442644232536 |
oct | 54343676533337 |
9 | 11728470181034 |
10 | 3054241494751 |
11 | a78329777597 |
12 | 413b23369027 |
13 | 192024246625 |
14 | a7b7ca8131d |
15 | 546ab662d51 |
hex | 2c71efab6df |
3054241494751 has 2 divisors, whose sum is σ = 3054241494752. Its totient is φ = 3054241494750.
The previous prime is 3054241494709. The next prime is 3054241494881. The reversal of 3054241494751 is 1574941424503.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3054241494751 is a prime.
It is a super-2 number, since 2×30542414947512 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3054241494695 and 3054241494704.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3054241414751) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1527120747375 + 1527120747376.
It is an arithmetic number, because the mean of its divisors is an integer number (1527120747376).
Almost surely, 23054241494751 is an apocalyptic number.
3054241494751 is a deficient number, since it is larger than the sum of its proper divisors (1).
3054241494751 is an equidigital number, since it uses as much as digits as its factorization.
3054241494751 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2419200, while the sum is 49.
The spelling of 3054241494751 in words is "three trillion, fifty-four billion, two hundred forty-one million, four hundred ninety-four thousand, seven hundred fifty-one".
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