Base | Representation |
---|---|
bin | 1101111000111011000000… |
… | …11010100111010001111001 |
3 | 11000010220011020200001212112 |
4 | 12330131200122213101321 |
5 | 13000404312241444400 |
6 | 144543153100422105 |
7 | 6301445143443050 |
oct | 674354032472171 |
9 | 130126136601775 |
10 | 30543130031225 |
11 | 98062a5710359 |
12 | 3513568547935 |
13 | 1407287c50856 |
14 | 77841c751397 |
15 | 37e76c0c0835 |
hex | 1bc7606a7479 |
30543130031225 has 48 divisors (see below), whose sum is σ = 43310391790848. Its totient is φ = 20931084599040.
The previous prime is 30543130031153. The next prime is 30543130031231. The reversal of 30543130031225 is 52213003134503.
It is not a de Polignac number, because 30543130031225 - 234 = 30525950162041 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 30543130031191 and 30543130031200.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2818406507 + ... + 2818417343.
It is an arithmetic number, because the mean of its divisors is an integer number (902299828976).
Almost surely, 230543130031225 is an apocalyptic number.
30543130031225 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
It is an amenable number.
30543130031225 is a deficient number, since it is larger than the sum of its proper divisors (12767261759623).
30543130031225 is a wasteful number, since it uses less digits than its factorization.
30543130031225 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19194 (or 19189 counting only the distinct ones).
The product of its (nonzero) digits is 32400, while the sum is 32.
Adding to 30543130031225 its reverse (52213003134503), we get a palindrome (82756133165728).
The spelling of 30543130031225 in words is "thirty trillion, five hundred forty-three billion, one hundred thirty million, thirty-one thousand, two hundred twenty-five".
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