Base | Representation |
---|---|
bin | 1101111001001111010100… |
… | …01100000011000010001111 |
3 | 11000011221021222112010211022 |
4 | 12330213222030003002033 |
5 | 13001044124014400101 |
6 | 144552154522544355 |
7 | 6302312244536354 |
oct | 674475214030217 |
9 | 130157258463738 |
10 | 30554031403151 |
11 | 980a98a204443 |
12 | 35156ab3680bb |
13 | 14083045c4c99 |
14 | 778b744aa62b |
15 | 37eba917ba1b |
hex | 1bc9ea30308f |
30554031403151 has 2 divisors, whose sum is σ = 30554031403152. Its totient is φ = 30554031403150.
The previous prime is 30554031403123. The next prime is 30554031403169. The reversal of 30554031403151 is 15130413045503.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-30554031403151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (30554031403111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15277015701575 + 15277015701576.
It is an arithmetic number, because the mean of its divisors is an integer number (15277015701576).
Almost surely, 230554031403151 is an apocalyptic number.
30554031403151 is a deficient number, since it is larger than the sum of its proper divisors (1).
30554031403151 is an equidigital number, since it uses as much as digits as its factorization.
30554031403151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54000, while the sum is 35.
Adding to 30554031403151 its reverse (15130413045503), we get a palindrome (45684444448654).
The spelling of 30554031403151 in words is "thirty trillion, five hundred fifty-four billion, thirty-one million, four hundred three thousand, one hundred fifty-one".
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