Base | Representation |
---|---|
bin | 101100011101101010010… |
… | …011101101101000001101 |
3 | 101211002210102021122220021 |
4 | 230131222103231220031 |
5 | 400030133324044411 |
6 | 10255402454422141 |
7 | 433516161344101 |
oct | 54355223555015 |
9 | 11732712248807 |
10 | 3055505299981 |
11 | a789180a3122 |
12 | 414216661951 |
13 | 19219601aa84 |
14 | a7c5c85d901 |
15 | 547325a3a71 |
hex | 2c76a4eda0d |
3055505299981 has 2 divisors, whose sum is σ = 3055505299982. Its totient is φ = 3055505299980.
The previous prime is 3055505299963. The next prime is 3055505300059. The reversal of 3055505299981 is 1899925055503.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3054574134756 + 931165225 = 1747734^2 + 30515^2 .
It is an emirp because it is prime and its reverse (1899925055503) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3055505299981 - 25 = 3055505299949 is a prime.
It is a super-2 number, since 2×30555052999812 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3055505299901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1527752649990 + 1527752649991.
It is an arithmetic number, because the mean of its divisors is an integer number (1527752649991).
Almost surely, 23055505299981 is an apocalyptic number.
It is an amenable number.
3055505299981 is a deficient number, since it is larger than the sum of its proper divisors (1).
3055505299981 is an equidigital number, since it uses as much as digits as its factorization.
3055505299981 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21870000, while the sum is 61.
The spelling of 3055505299981 in words is "three trillion, fifty-five billion, five hundred five million, two hundred ninety-nine thousand, nine hundred eighty-one".
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