Base | Representation |
---|---|
bin | 101100011110100000110… |
… | …111001001101100000001 |
3 | 101211012011012111200002022 |
4 | 230132200313021230001 |
5 | 400034022130401432 |
6 | 10300033351531225 |
7 | 433550644046405 |
oct | 54364067115401 |
9 | 11735135450068 |
10 | 3056420559617 |
11 | a792477a8247 |
12 | 414431089b15 |
13 | 1922b0828019 |
14 | a7d0822d105 |
15 | 54787ae6b12 |
hex | 2c7a0dc9b01 |
3056420559617 has 2 divisors, whose sum is σ = 3056420559618. Its totient is φ = 3056420559616.
The previous prime is 3056420559607. The next prime is 3056420559623. The reversal of 3056420559617 is 7169550246503.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1708350947521 + 1348069612096 = 1307039^2 + 1161064^2 .
It is a cyclic number.
It is not a de Polignac number, because 3056420559617 - 214 = 3056420543233 is a prime.
It is not a weakly prime, because it can be changed into another prime (3056420559607) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1528210279808 + 1528210279809.
It is an arithmetic number, because the mean of its divisors is an integer number (1528210279809).
Almost surely, 23056420559617 is an apocalyptic number.
It is an amenable number.
3056420559617 is a deficient number, since it is larger than the sum of its proper divisors (1).
3056420559617 is an equidigital number, since it uses as much as digits as its factorization.
3056420559617 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6804000, while the sum is 53.
The spelling of 3056420559617 in words is "three trillion, fifty-six billion, four hundred twenty million, five hundred fifty-nine thousand, six hundred seventeen".
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