Base | Representation |
---|---|
bin | 101100110110000101010… |
… | …100010000100000010111 |
3 | 101220121110221100121022012 |
4 | 230312011110100200113 |
5 | 400442334411401242 |
6 | 10315420523054435 |
7 | 435435045522245 |
oct | 54660524204027 |
9 | 11817427317265 |
10 | 3081728231447 |
11 | a88a54278708 |
12 | 41931467141b |
13 | 1947b4a17278 |
14 | a92293c5795 |
15 | 552697e1282 |
hex | 2cd85510817 |
3081728231447 has 2 divisors, whose sum is σ = 3081728231448. Its totient is φ = 3081728231446.
The previous prime is 3081728231419. The next prime is 3081728231473. The reversal of 3081728231447 is 7441328271803.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3081728231447 - 28 = 3081728231191 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3081728231395 and 3081728231404.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3081728231147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1540864115723 + 1540864115724.
It is an arithmetic number, because the mean of its divisors is an integer number (1540864115724).
Almost surely, 23081728231447 is an apocalyptic number.
3081728231447 is a deficient number, since it is larger than the sum of its proper divisors (1).
3081728231447 is an equidigital number, since it uses as much as digits as its factorization.
3081728231447 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1806336, while the sum is 50.
The spelling of 3081728231447 in words is "three trillion, eighty-one billion, seven hundred twenty-eight million, two hundred thirty-one thousand, four hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •