Base | Representation |
---|---|
bin | 1001000000110110100… |
… | …10010001110110111111 |
3 | 1002121101012120111020122 |
4 | 10200123102101312333 |
5 | 20033224012000022 |
6 | 354134435405155 |
7 | 31242353436425 |
oct | 4403322216677 |
9 | 1077335514218 |
10 | 309695421887 |
11 | 10a382aa0265 |
12 | 500304537bb |
13 | 232866a7537 |
14 | 10dbca5d115 |
15 | 80c8956742 |
hex | 481b491dbf |
309695421887 has 2 divisors, whose sum is σ = 309695421888. Its totient is φ = 309695421886.
The previous prime is 309695421823. The next prime is 309695421911. The reversal of 309695421887 is 788124596903.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 309695421887 - 26 = 309695421823 is a prime.
It is a super-3 number, since 3×3096954218873 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (309695423887) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 154847710943 + 154847710944.
It is an arithmetic number, because the mean of its divisors is an integer number (154847710944).
It is a 1-persistent number, because it is pandigital, but 2⋅309695421887 = 619390843774 is not.
Almost surely, 2309695421887 is an apocalyptic number.
309695421887 is a deficient number, since it is larger than the sum of its proper divisors (1).
309695421887 is an equidigital number, since it uses as much as digits as its factorization.
309695421887 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 26127360, while the sum is 62.
The spelling of 309695421887 in words is "three hundred nine billion, six hundred ninety-five million, four hundred twenty-one thousand, eight hundred eighty-seven".
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