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310004000221 is a prime number
BaseRepresentation
bin1001000001011011010…
…11011010010111011101
31002122011201012220010211
410200231223122113131
520034342011001341
6354225221332421
731253121344626
oct4405553322735
91078151186124
10310004000221
1110a5211a3783
12500b7867111
13233055b9a76
141100ba26a4d
1580e5aac181
hex482dada5dd

310004000221 has 2 divisors, whose sum is σ = 310004000222. Its totient is φ = 310004000220.

The previous prime is 310004000149. The next prime is 310004000233. The reversal of 310004000221 is 122000400013.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 255212894596 + 54791105625 = 505186^2 + 234075^2 .

It is an emirp because it is prime and its reverse (122000400013) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 310004000221 - 213 = 310003992029 is a prime.

It is a super-2 number, since 2×3100040002212 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (310004000281) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155002000110 + 155002000111.

It is an arithmetic number, because the mean of its divisors is an integer number (155002000111).

Almost surely, 2310004000221 is an apocalyptic number.

It is an amenable number.

310004000221 is a deficient number, since it is larger than the sum of its proper divisors (1).

310004000221 is an equidigital number, since it uses as much as digits as its factorization.

310004000221 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 13.

Adding to 310004000221 its reverse (122000400013), we get a palindrome (432004400234).

The spelling of 310004000221 in words is "three hundred ten billion, four million, two hundred twenty-one", and thus it is an aban number.