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310011000053 is a prime number
BaseRepresentation
bin1001000001011100001…
…10000111010011110101
31002122012012101112002212
410200232012013103311
520034400304000203
6354230031343205
731253235010406
oct4405606072365
91078165345085
10310011000053
1110a525144867
12500ba081b05
1323306b9ab91
141100c9299ad
1580e64e11d8
hex482e1874f5

310011000053 has 2 divisors, whose sum is σ = 310011000054. Its totient is φ = 310011000052.

The previous prime is 310010999983. The next prime is 310011000083. The reversal of 310011000053 is 350000110013.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 275018434084 + 34992565969 = 524422^2 + 187063^2 .

It is a cyclic number.

It is not a de Polignac number, because 310011000053 - 220 = 310009951477 is a prime.

It is a super-2 number, since 2×3100110000532 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (310011000083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155005500026 + 155005500027.

It is an arithmetic number, because the mean of its divisors is an integer number (155005500027).

Almost surely, 2310011000053 is an apocalyptic number.

It is an amenable number.

310011000053 is a deficient number, since it is larger than the sum of its proper divisors (1).

310011000053 is an equidigital number, since it uses as much as digits as its factorization.

310011000053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 45, while the sum is 14.

Adding to 310011000053 its reverse (350000110013), we get a palindrome (660011110066).

The spelling of 310011000053 in words is "three hundred ten billion, eleven million, fifty-three", and thus it is an aban number.