Base | Representation |
---|---|
bin | 11100110111110011… |
… | …110110101001000111 |
3 | 2222000112001121122102 |
4 | 130313303312221013 |
5 | 1001442241023421 |
6 | 22124113222315 |
7 | 2145144045065 |
oct | 346763665107 |
9 | 88015047572 |
10 | 31001111111 |
11 | 12169356693 |
12 | 601226199b |
13 | 2c00900c39 |
14 | 17013a5035 |
15 | c1697960b |
hex | 737cf6a47 |
31001111111 has 2 divisors, whose sum is σ = 31001111112. Its totient is φ = 31001111110.
The previous prime is 31001111069. The next prime is 31001111137. The reversal of 31001111111 is 11111110013.
It is a strong prime.
It is an emirp because it is prime and its reverse (11111110013) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31001111111 - 26 = 31001111047 is a prime.
It is a super-2 number, since 2×310011111112 (a number of 22 digits) contains 22 as substring.
31001111111 is a modest number, since divided by 111111 gives 31001 as remainder.
It is a junction number, because it is equal to n+sod(n) for n = 31001111092 and 31001111101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31001111161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15500555555 + 15500555556.
It is an arithmetic number, because the mean of its divisors is an integer number (15500555556).
Almost surely, 231001111111 is an apocalyptic number.
31001111111 is a deficient number, since it is larger than the sum of its proper divisors (1).
31001111111 is an equidigital number, since it uses as much as digits as its factorization.
31001111111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3, while the sum is 11.
Adding to 31001111111 its reverse (11111110013), we get a palindrome (42112221124).
The spelling of 31001111111 in words is "thirty-one billion, one million, one hundred eleven thousand, one hundred eleven".
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