Base | Representation |
---|---|
bin | 1001000001011101100… |
… | …00001000000001011111 |
3 | 1002122012222010001001122 |
4 | 10200232300020001133 |
5 | 20034411113404043 |
6 | 354231103401155 |
7 | 31253430426242 |
oct | 4405660100137 |
9 | 1078188101048 |
10 | 310022013023 |
11 | 10a530386a98 |
12 | 501018b31bb |
13 | 23309255828 |
14 | 11010195259 |
15 | 80e7469368 |
hex | 482ec0805f |
310022013023 has 2 divisors, whose sum is σ = 310022013024. Its totient is φ = 310022013022.
The previous prime is 310022013001. The next prime is 310022013079. The reversal of 310022013023 is 320310220013.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 310022013023 - 212 = 310022008927 is a prime.
It is a super-2 number, since 2×3100220130232 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 310022012992 and 310022013010.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (310022013823) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155011006511 + 155011006512.
It is an arithmetic number, because the mean of its divisors is an integer number (155011006512).
Almost surely, 2310022013023 is an apocalyptic number.
310022013023 is a deficient number, since it is larger than the sum of its proper divisors (1).
310022013023 is an equidigital number, since it uses as much as digits as its factorization.
310022013023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 17.
Adding to 310022013023 its reverse (320310220013), we get a palindrome (630332233036).
The spelling of 310022013023 in words is "three hundred ten billion, twenty-two million, thirteen thousand, twenty-three".
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