Base | Representation |
---|---|
bin | 11100111000001000… |
… | …001110001011101011 |
3 | 2222000220002212210021 |
4 | 130320020032023223 |
5 | 1002000122403121 |
6 | 22124423501311 |
7 | 2145240323416 |
oct | 347010161353 |
9 | 88026085707 |
10 | 31006450411 |
11 | 12171373132 |
12 | 6013bb7837 |
13 | 2c01a502a1 |
14 | 1701d94b7d |
15 | c17181641 |
hex | 73820e2eb |
31006450411 has 2 divisors, whose sum is σ = 31006450412. Its totient is φ = 31006450410.
The previous prime is 31006450403. The next prime is 31006450421. The reversal of 31006450411 is 11405460013.
It is a weak prime.
It is an emirp because it is prime and its reverse (11405460013) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31006450411 - 23 = 31006450403 is a prime.
It is a super-2 number, since 2×310064504112 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (31006450421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15503225205 + 15503225206.
It is an arithmetic number, because the mean of its divisors is an integer number (15503225206).
Almost surely, 231006450411 is an apocalyptic number.
31006450411 is a deficient number, since it is larger than the sum of its proper divisors (1).
31006450411 is an equidigital number, since it uses as much as digits as its factorization.
31006450411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 25.
The spelling of 31006450411 in words is "thirty-one billion, six million, four hundred fifty thousand, four hundred eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •