Base | Representation |
---|---|
bin | 1001000001110100010… |
… | …01011111111110110011 |
3 | 1002122201021220001200011 |
4 | 10200322021133332303 |
5 | 20040304040323011 |
6 | 354302053435351 |
7 | 31261241546002 |
oct | 4407211377663 |
9 | 1078637801604 |
10 | 310213214131 |
11 | 10a6192aa237 |
12 | 5015593bb57 |
13 | 23339a4bb92 |
14 | 1102b726c39 |
15 | 8109136621 |
hex | 483a25ffb3 |
310213214131 has 2 divisors, whose sum is σ = 310213214132. Its totient is φ = 310213214130.
The previous prime is 310213214117. The next prime is 310213214153. The reversal of 310213214131 is 131412312013.
It is an a-pointer prime, because the next prime (310213214153) can be obtained adding 310213214131 to its sum of digits (22).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 310213214131 - 215 = 310213181363 is a prime.
It is a super-2 number, since 2×3102132141312 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (310213224131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155106607065 + 155106607066.
It is an arithmetic number, because the mean of its divisors is an integer number (155106607066).
Almost surely, 2310213214131 is an apocalyptic number.
310213214131 is a deficient number, since it is larger than the sum of its proper divisors (1).
310213214131 is an equidigital number, since it uses as much as digits as its factorization.
310213214131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 310213214131 its reverse (131412312013), we get a palindrome (441625526144).
The spelling of 310213214131 in words is "three hundred ten billion, two hundred thirteen million, two hundred fourteen thousand, one hundred thirty-one".
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