Base | Representation |
---|---|
bin | 101101001010000000011… |
… | …011001101001001100111 |
3 | 101222122200211122000002122 |
4 | 231022000123031021213 |
5 | 401320142434044421 |
6 | 10333315404300155 |
7 | 440123142215033 |
oct | 55120033151147 |
9 | 11878624560078 |
10 | 3103121003111 |
11 | a970319a9698 |
12 | 4214a4b4165b |
13 | 196813b0c53c |
14 | aa29865b1c3 |
15 | 55abc9752ab |
hex | 2d2806cd267 |
3103121003111 has 2 divisors, whose sum is σ = 3103121003112. Its totient is φ = 3103121003110.
The previous prime is 3103121003077. The next prime is 3103121003123. The reversal of 3103121003111 is 1113001213013.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3103121003111 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3103121003111.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3103121003141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1551560501555 + 1551560501556.
It is an arithmetic number, because the mean of its divisors is an integer number (1551560501556).
Almost surely, 23103121003111 is an apocalyptic number.
3103121003111 is a deficient number, since it is larger than the sum of its proper divisors (1).
3103121003111 is an equidigital number, since it uses as much as digits as its factorization.
3103121003111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 3103121003111 its reverse (1113001213013), we get a palindrome (4216122216124).
The spelling of 3103121003111 in words is "three trillion, one hundred three billion, one hundred twenty-one million, three thousand, one hundred eleven".
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