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310412100201121 is a prime number
BaseRepresentation
bin100011010010100010111001…
…0111101110110101010100001
31111201002002212222102010010101
41012211011302331312222201
5311141242440122413441
63020105203350502401
7122245351134062602
oct10645056275665241
91451062788363111
10310412100201121
118a9a803a156056
122a993b40364a01
1310428973a17399
145692050b89da9
1525d47e7610231
hex11a5172f76aa1

310412100201121 has 2 divisors, whose sum is σ = 310412100201122. Its totient is φ = 310412100201120.

The previous prime is 310412100201089. The next prime is 310412100201131. The reversal of 310412100201121 is 121102001214013.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 247910189386896 + 62501910814225 = 15745164^2 + 7905815^2 .

It is an emirp because it is prime and its reverse (121102001214013) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 310412100201121 - 25 = 310412100201089 is a prime.

It is not a weakly prime, because it can be changed into another prime (310412100201131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155206050100560 + 155206050100561.

It is an arithmetic number, because the mean of its divisors is an integer number (155206050100561).

Almost surely, 2310412100201121 is an apocalyptic number.

It is an amenable number.

310412100201121 is a deficient number, since it is larger than the sum of its proper divisors (1).

310412100201121 is an equidigital number, since it uses as much as digits as its factorization.

310412100201121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 310412100201121 its reverse (121102001214013), we get a palindrome (431514101415134).

The spelling of 310412100201121 in words is "three hundred ten trillion, four hundred twelve billion, one hundred million, two hundred one thousand, one hundred twenty-one".