Base | Representation |
---|---|
bin | 101101001011110011101… |
… | …010101110000101111001 |
3 | 101222211200120202021200012 |
4 | 231023303222232011321 |
5 | 401333122414400131 |
6 | 10334235312551305 |
7 | 440222100230405 |
oct | 55136352560571 |
9 | 11884616667605 |
10 | 3105054450041 |
11 | a97934319a15 |
12 | 421944552535 |
13 | 196a61553c8b |
14 | aa3dd350105 |
15 | 55b8258d52b |
hex | 2d2f3aae179 |
3105054450041 has 2 divisors, whose sum is σ = 3105054450042. Its totient is φ = 3105054450040.
The previous prime is 3105054450013. The next prime is 3105054450049. The reversal of 3105054450041 is 1400544505013.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3031094928016 + 73959522025 = 1741004^2 + 271955^2 .
It is a cyclic number.
It is not a de Polignac number, because 3105054450041 - 26 = 3105054449977 is a prime.
It is not a weakly prime, because it can be changed into another prime (3105054450049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1552527225020 + 1552527225021.
It is an arithmetic number, because the mean of its divisors is an integer number (1552527225021).
Almost surely, 23105054450041 is an apocalyptic number.
It is an amenable number.
3105054450041 is a deficient number, since it is larger than the sum of its proper divisors (1).
3105054450041 is an equidigital number, since it uses as much as digits as its factorization.
3105054450041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24000, while the sum is 32.
Adding to 3105054450041 its reverse (1400544505013), we get a palindrome (4505598955054).
The spelling of 3105054450041 in words is "three trillion, one hundred five billion, fifty-four million, four hundred fifty thousand, forty-one".
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