31100004331232 has 12 divisors (see below), whose sum is σ = 61228133527176. Its totient is φ = 15550002165600.

The previous prime is 31100004331189. The next prime is 31100004331259. The reversal of 31100004331232 is 23213340000113.

It is a junction number, because it is equal to n+sod(n) for n = 31100004331198 and 31100004331207.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 485937567644 + ... + 485937567707.

It is an arithmetic number, because the mean of its divisors is an integer number (5102344460598).

Almost surely, 2^{31100004331232} is an apocalyptic number.

31100004331232 is a gapful number since it is divisible by the number (32) formed by its first and last digit.

It is an amenable number.

31100004331232 is a deficient number, since it is larger than the sum of its proper divisors (30128129195944).

31100004331232 is an equidigital number, since it uses as much as digits as its factorization.

31100004331232 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 971875135361 (or 971875135353 counting only the distinct ones).

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 31100004331232 its reverse (23213340000113), we get a palindrome (54313344331345).

The spelling of 31100004331232 in words is "thirty-one trillion, one hundred billion, four million, three hundred thirty-one thousand, two hundred thirty-two".