311006431 has 2 divisors, whose sum is σ = 311006432. Its totient is φ = 311006430.

The previous prime is 311006417. The next prime is 311006513. The reversal of 311006431 is 134600113.

It is a weak prime.

It is an emirp because it is prime and its reverse (134600113) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 311006431 - 2¹¹ = 311004383 is a prime.

It is a super-2 number, since 2×311006431² = 193450000246715522, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 311006399 and 311006408.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (311036431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155503215 + 155503216.

It is an arithmetic number, because the mean of its divisors is an integer number (155503216).

Almost surely, 2^311006431 is an apocalyptic number.

311006431 is a deficient number, since it is larger than the sum of its proper divisors (1).

311006431 is an equidigital number, since it uses as much as digits as its factorization.

311006431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 19.

The square root of 311006431 is about 17635.3744218829. The cubic root of 311006431 is about 677.5215651964.

Adding to 311006431 its reverse (134600113), we get a palindrome (445606544).

The spelling of 311006431 in words is "three hundred eleven million, six thousand, four hundred thirty-one".