Base | Representation |
---|---|
bin | 101101010000100000011… |
… | …010000001000100000000 |
3 | 102000022201012212110021221 |
4 | 231100200122001010000 |
5 | 401423441100411222 |
6 | 10340432112524424 |
7 | 440461114633405 |
oct | 55204032010400 |
9 | 12008635773257 |
10 | 3110100013312 |
11 | a99a93417316 |
12 | 422912250714 |
13 | 197386976686 |
14 | aa75b4b22ac |
15 | 55d7a4e50c7 |
hex | 2d420681100 |
3110100013312 has 18 divisors (see below), whose sum is σ = 6208051198958. Its totient is φ = 1555050006528.
The previous prime is 3110100013303. The next prime is 3110100013333. The reversal of 3110100013312 is 2133100010113.
It can be written as a sum of positive squares in only one way, i.e., 2509512212736 + 600587800576 = 1584144^2 + 774976^2 .
It is a Harshad number since it is a multiple of its sum of digits (16).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6074413833 + ... + 6074414344.
Almost surely, 23110100013312 is an apocalyptic number.
3110100013312 is a gapful number since it is divisible by the number (32) formed by its first and last digit.
It is an amenable number.
3110100013312 is a deficient number, since it is larger than the sum of its proper divisors (3097951185646).
3110100013312 is an equidigital number, since it uses as much as digits as its factorization.
3110100013312 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12148828193 (or 12148828179 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 3110100013312 its reverse (2133100010113), we get a palindrome (5243200023425).
The spelling of 3110100013312 in words is "three trillion, one hundred ten billion, one hundred million, thirteen thousand, three hundred twelve".
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