Base | Representation |
---|---|
bin | 100011010110111010110001… |
… | …1010101010000001110011101 |
3 | 1111210012120021000021002211011 |
4 | 1012231311203111100032131 |
5 | 311231114344112233432 |
6 | 3021245243324255221 |
7 | 122336646243233353 |
oct | 10655654325201635 |
9 | 1453176230232734 |
10 | 311013133321117 |
11 | 90109a24733a27 |
12 | 2aa705190a1511 |
13 | 10470549709ba6 |
14 | 56b318a31d7d3 |
15 | 25e5273002847 |
hex | 11add6355039d |
311013133321117 has 2 divisors, whose sum is σ = 311013133321118. Its totient is φ = 311013133321116.
The previous prime is 311013133321109. The next prime is 311013133321129. The reversal of 311013133321117 is 711123331310113.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 255050929258596 + 55962204062521 = 15970314^2 + 7480789^2 .
It is an emirp because it is prime and its reverse (711123331310113) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 311013133321117 - 23 = 311013133321109 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (311013133322117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155506566660558 + 155506566660559.
It is an arithmetic number, because the mean of its divisors is an integer number (155506566660559).
Almost surely, 2311013133321117 is an apocalyptic number.
It is an amenable number.
311013133321117 is a deficient number, since it is larger than the sum of its proper divisors (1).
311013133321117 is an equidigital number, since it uses as much as digits as its factorization.
311013133321117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3402, while the sum is 31.
The spelling of 311013133321117 in words is "three hundred eleven trillion, thirteen billion, one hundred thirty-three million, three hundred twenty-one thousand, one hundred seventeen".
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