Base | Representation |
---|---|
bin | 100011010110111011010001… |
… | …1101011111100011011111001 |
3 | 1111210012200001020220001011111 |
4 | 1012231312203223330123321 |
5 | 311231124102012324233 |
6 | 3021245542414000321 |
7 | 122340015063400006 |
oct | 10655664353743371 |
9 | 1453180036801144 |
10 | 311014213011193 |
11 | 9010a42913707a |
12 | 2aa7077a7a60a1 |
13 | 1047068c2c9363 |
14 | 56b324d8928ad |
15 | 25e52d7bc5acd |
hex | 11adda3afc6f9 |
311014213011193 has 2 divisors, whose sum is σ = 311014213011194. Its totient is φ = 311014213011192.
The previous prime is 311014213011133. The next prime is 311014213011209. The reversal of 311014213011193 is 391110312410113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 284776020094864 + 26238192916329 = 16875308^2 + 5122323^2 .
It is a cyclic number.
It is not a de Polignac number, because 311014213011193 - 229 = 311013676140281 is a prime.
It is not a weakly prime, because it can be changed into another prime (311014213011113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155507106505596 + 155507106505597.
It is an arithmetic number, because the mean of its divisors is an integer number (155507106505597).
Almost surely, 2311014213011193 is an apocalyptic number.
It is an amenable number.
311014213011193 is a deficient number, since it is larger than the sum of its proper divisors (1).
311014213011193 is an equidigital number, since it uses as much as digits as its factorization.
311014213011193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 31.
The spelling of 311014213011193 in words is "three hundred eleven trillion, fourteen billion, two hundred thirteen million, eleven thousand, one hundred ninety-three".
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