311014213011133 has 2 divisors, whose sum is σ = 311014213011134. Its totient is φ = 311014213011132.

The previous prime is 311014213011127. The next prime is 311014213011193. The reversal of 311014213011133 is 331110312410113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 235597111783929 + 75417101227204 = 15349173^2 + 8684302^2 .

It is a cyclic number.

It is not a de Polignac number, because 311014213011133 - 2⁵ = 311014213011101 is a prime.

It is a super-2 number, since 2×311014213011133² (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 311014213011098 and 311014213011107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (311014213011113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155507106505566 + 155507106505567.

It is an arithmetic number, because the mean of its divisors is an integer number (155507106505567).

Almost surely, 2^{311014213011133} is an apocalyptic number.

It is an amenable number.

311014213011133 is a deficient number, since it is larger than the sum of its proper divisors (1).

311014213011133 is an equidigital number, since it uses as much as digits as its factorization.

311014213011133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 25.

Adding to 311014213011133 its reverse (331110312410113), we get a palindrome (642124525421246).

The spelling of 311014213011133 in words is "three hundred eleven trillion, fourteen billion, two hundred thirteen million, eleven thousand, one hundred thirty-three".