Base | Representation |
---|---|
bin | 1110001001001100001100… |
… | …01101111110010001010011 |
3 | 11002010022222112002122100211 |
4 | 13010212012031332101103 |
5 | 13034034110130001321 |
6 | 150052040113224551 |
7 | 6360024165000655 |
oct | 704460615762123 |
9 | 132108875078324 |
10 | 31102110000211 |
11 | 9a013702a0478 |
12 | 35a3969862157 |
13 | 1447bbb3c7053 |
14 | 7974c8b846d5 |
15 | 38e085b1a0e1 |
hex | 1c498637e453 |
31102110000211 has 2 divisors, whose sum is σ = 31102110000212. Its totient is φ = 31102110000210.
The previous prime is 31102110000191. The next prime is 31102110000223. The reversal of 31102110000211 is 11200001120113.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31102110000211 - 221 = 31102107903059 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 31102110000191 and 31102110000200.
It is not a weakly prime, because it can be changed into another prime (31102110090211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15551055000105 + 15551055000106.
It is an arithmetic number, because the mean of its divisors is an integer number (15551055000106).
Almost surely, 231102110000211 is an apocalyptic number.
31102110000211 is a deficient number, since it is larger than the sum of its proper divisors (1).
31102110000211 is an equidigital number, since it uses as much as digits as its factorization.
31102110000211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 13.
Adding to 31102110000211 its reverse (11200001120113), we get a palindrome (42302111120324).
The spelling of 31102110000211 in words is "thirty-one trillion, one hundred two billion, one hundred ten million, two hundred eleven", and thus it is an aban number.
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