Base | Representation |
---|---|
bin | 100011010110111111100000… |
… | …1111111001101110110100110 |
3 | 1111210020112112022221201202012 |
4 | 1012231333001333031312212 |
5 | 311231301220144024332 |
6 | 3021254045310114222 |
7 | 122340456411605114 |
oct | 10655770177156646 |
9 | 1453215468851665 |
10 | 311023311314342 |
11 | 9011327796a980 |
12 | 2aa724997ab972 |
13 | 104714ac2479a3 |
14 | 56b3873d76ab4 |
15 | 25e566b81e3b2 |
hex | 11adfc1fcdda6 |
311023311314342 has 8 divisors (see below), whose sum is σ = 508947236696232. Its totient is φ = 141374232415600.
The previous prime is 311023311314327. The next prime is 311023311314503. The reversal of 311023311314342 is 243413113320113.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 311023311314299 and 311023311314308.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7068711620759 + ... + 7068711620802.
It is an arithmetic number, because the mean of its divisors is an integer number (63618404587029).
Almost surely, 2311023311314342 is an apocalyptic number.
311023311314342 is a deficient number, since it is larger than the sum of its proper divisors (197923925381890).
311023311314342 is a wasteful number, since it uses less digits than its factorization.
311023311314342 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14137423241574.
The product of its (nonzero) digits is 15552, while the sum is 32.
Adding to 311023311314342 its reverse (243413113320113), we get a palindrome (554436424634455).
The spelling of 311023311314342 in words is "three hundred eleven trillion, twenty-three billion, three hundred eleven million, three hundred fourteen thousand, three hundred forty-two".
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