Base | Representation |
---|---|
bin | 1110001001001110000110… |
… | …01001110100011000101011 |
3 | 11002010102121202202221021201 |
4 | 13010213003021310120223 |
5 | 13034043203333240243 |
6 | 150052325353145031 |
7 | 6360061420405666 |
oct | 704470311643053 |
9 | 132112552687251 |
10 | 31103132321323 |
11 | 9a0184537a457 |
12 | 35a3bb40bb177 |
13 | 144802214ac9a |
14 | 7975848626dd |
15 | 38e0e575a04d |
hex | 1c49c327462b |
31103132321323 has 2 divisors, whose sum is σ = 31103132321324. Its totient is φ = 31103132321322.
The previous prime is 31103132321291. The next prime is 31103132321357. The reversal of 31103132321323 is 32312323130113.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31103132321323 - 25 = 31103132321291 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 31103132321291 and 31103132321300.
It is not a weakly prime, because it can be changed into another prime (31103132322323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15551566160661 + 15551566160662.
It is an arithmetic number, because the mean of its divisors is an integer number (15551566160662).
Almost surely, 231103132321323 is an apocalyptic number.
31103132321323 is a deficient number, since it is larger than the sum of its proper divisors (1).
31103132321323 is an equidigital number, since it uses as much as digits as its factorization.
31103132321323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5832, while the sum is 28.
Adding to 31103132321323 its reverse (32312323130113), we get a palindrome (63415455451436).
The spelling of 31103132321323 in words is "thirty-one trillion, one hundred three billion, one hundred thirty-two million, three hundred twenty-one thousand, three hundred twenty-three".
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