3110404040113 has 2 divisors, whose sum is σ = 3110404040114. Its totient is φ = 3110404040112.

The previous prime is 3110404040087. The next prime is 3110404040173.

It is a happy number.

3110404040113 is nontrivially palindromic in base 10.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2809203940624 + 301200099489 = 1676068^2 + 548817^2 .

It is a palprime.

It is a cyclic number.

It is not a de Polignac number, because 3110404040113 - 2¹³ = 3110404031921 is a prime.

It is a super-2 number, since 2×3110404040113² (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (3110404040173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555202020056 + 1555202020057.

It is an arithmetic number, because the mean of its divisors is an integer number (1555202020057).

Almost surely, 2^{3110404040113} is an apocalyptic number.

It is an amenable number.

3110404040113 is a deficient number, since it is larger than the sum of its proper divisors (1).

3110404040113 is an equidigital number, since it uses as much as digits as its factorization.

3110404040113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 22.

Multiplying 3110404040113 by its sum of digits (22), we get a palindrome (68428888882486).

The spelling of 3110404040113 in words is "three trillion, one hundred ten billion, four hundred four million, forty thousand, one hundred thirteen".