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31105450503437 is a prime number
BaseRepresentation
bin1110001001010010011010…
…10100111110110100001101
311002010122121022211210022112
413010221031110332310031
513034112430312102222
6150053351403553405
76360203026545302
oct704511524766415
9132118538753275
1031105450503437
119a02824989a42
1235a454052b865
1314483014bac8b
147977246a50a9
1538e1ce01dbe2
hex1c4a4d53ed0d

31105450503437 has 2 divisors, whose sum is σ = 31105450503438. Its totient is φ = 31105450503436.

The previous prime is 31105450503431. The next prime is 31105450503487. The reversal of 31105450503437 is 73430505450113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 21319884083716 + 9785566419721 = 4617346^2 + 3128189^2 .

It is a cyclic number.

It is not a de Polignac number, because 31105450503437 - 214 = 31105450487053 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 31105450503394 and 31105450503403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31105450503431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15552725251718 + 15552725251719.

It is an arithmetic number, because the mean of its divisors is an integer number (15552725251719).

Almost surely, 231105450503437 is an apocalyptic number.

It is an amenable number.

31105450503437 is a deficient number, since it is larger than the sum of its proper divisors (1).

31105450503437 is an equidigital number, since it uses as much as digits as its factorization.

31105450503437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 378000, while the sum is 41.

The spelling of 31105450503437 in words is "thirty-one trillion, one hundred five billion, four hundred fifty million, five hundred three thousand, four hundred thirty-seven".