Base | Representation |
---|---|
bin | 100011010111100011010001… |
… | …1101011011011010011100101 |
3 | 1111210111212202201102001020212 |
4 | 1012233012203223123103211 |
5 | 311234031012212041123 |
6 | 3021353230224105205 |
7 | 122346145536545144 |
oct | 10657064353332345 |
9 | 1453455681361225 |
10 | 311100112221413 |
11 | 901428a8a930a9 |
12 | 2aa85352165205 |
13 | 104787cb66aab8 |
14 | 56b747bcc175b |
15 | 25e766401d878 |
hex | 11af1a3adb4e5 |
311100112221413 has 2 divisors, whose sum is σ = 311100112221414. Its totient is φ = 311100112221412.
The previous prime is 311100112221401. The next prime is 311100112221419. The reversal of 311100112221413 is 314122211001113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 300069629860324 + 11030482361089 = 17322518^2 + 3321217^2 .
It is a cyclic number.
It is not a de Polignac number, because 311100112221413 - 210 = 311100112220389 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (311100112221419) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155550056110706 + 155550056110707.
It is an arithmetic number, because the mean of its divisors is an integer number (155550056110707).
Almost surely, 2311100112221413 is an apocalyptic number.
It is an amenable number.
311100112221413 is a deficient number, since it is larger than the sum of its proper divisors (1).
311100112221413 is an equidigital number, since it uses as much as digits as its factorization.
311100112221413 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 288, while the sum is 23.
Adding to 311100112221413 its reverse (314122211001113), we get a palindrome (625222323222526).
The spelling of 311100112221413 in words is "three hundred eleven trillion, one hundred billion, one hundred twelve million, two hundred twenty-one thousand, four hundred thirteen".
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