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311100112221413 is a prime number
BaseRepresentation
bin100011010111100011010001…
…1101011011011010011100101
31111210111212202201102001020212
41012233012203223123103211
5311234031012212041123
63021353230224105205
7122346145536545144
oct10657064353332345
91453455681361225
10311100112221413
11901428a8a930a9
122aa85352165205
13104787cb66aab8
1456b747bcc175b
1525e766401d878
hex11af1a3adb4e5

311100112221413 has 2 divisors, whose sum is σ = 311100112221414. Its totient is φ = 311100112221412.

The previous prime is 311100112221401. The next prime is 311100112221419. The reversal of 311100112221413 is 314122211001113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 300069629860324 + 11030482361089 = 17322518^2 + 3321217^2 .

It is a cyclic number.

It is not a de Polignac number, because 311100112221413 - 210 = 311100112220389 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (311100112221419) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155550056110706 + 155550056110707.

It is an arithmetic number, because the mean of its divisors is an integer number (155550056110707).

Almost surely, 2311100112221413 is an apocalyptic number.

It is an amenable number.

311100112221413 is a deficient number, since it is larger than the sum of its proper divisors (1).

311100112221413 is an equidigital number, since it uses as much as digits as its factorization.

311100112221413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 23.

Adding to 311100112221413 its reverse (314122211001113), we get a palindrome (625222323222526).

The spelling of 311100112221413 in words is "three hundred eleven trillion, one hundred billion, one hundred twelve million, two hundred twenty-one thousand, four hundred thirteen".