Base | Representation |
---|---|
bin | 100011010111100011010010… |
… | …0001010010110111100100111 |
3 | 1111210111212210021200000011202 |
4 | 1012233012210022112330213 |
5 | 311234031021301030043 |
6 | 3021353231113553115 |
7 | 122346145665506333 |
oct | 10657064412267447 |
9 | 1453455707600152 |
10 | 311100120330023 |
11 | 90142902621232 |
12 | 2aa85354a1579b |
13 | 104788002497ab |
14 | 56b747cdd27c3 |
15 | 25e7664ac11b8 |
hex | 11af1a4296f27 |
311100120330023 has 2 divisors, whose sum is σ = 311100120330024. Its totient is φ = 311100120330022.
The previous prime is 311100120329941. The next prime is 311100120330121. The reversal of 311100120330023 is 320033021001113.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 311100120330023 - 214 = 311100120313639 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 311100120329977 and 311100120330004.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (311100120330823) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155550060165011 + 155550060165012.
It is an arithmetic number, because the mean of its divisors is an integer number (155550060165012).
Almost surely, 2311100120330023 is an apocalyptic number.
311100120330023 is a deficient number, since it is larger than the sum of its proper divisors (1).
311100120330023 is an equidigital number, since it uses as much as digits as its factorization.
311100120330023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 311100120330023 its reverse (320033021001113), we get a palindrome (631133141331136).
The spelling of 311100120330023 in words is "three hundred eleven trillion, one hundred billion, one hundred twenty million, three hundred thirty thousand, twenty-three".
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