Base | Representation |
---|---|
bin | 1110001001011010111100… |
… | …10011100011101101000011 |
3 | 11002011002102111120002010122 |
4 | 13010231132103203231003 |
5 | 13034201320224411321 |
6 | 150055430045050455 |
7 | 6360424360345526 |
oct | 704553623435503 |
9 | 132132374502118 |
10 | 31110030310211 |
11 | 9a04765089616 |
12 | 35a53ba256a2b |
13 | 1448881287c08 |
14 | 797a3aa26bbd |
15 | 38e39b1238ab |
hex | 1c4b5e4e3b43 |
31110030310211 has 2 divisors, whose sum is σ = 31110030310212. Its totient is φ = 31110030310210.
The previous prime is 31110030310199. The next prime is 31110030310223. The reversal of 31110030310211 is 11201303001113.
It is a balanced prime because it is at equal distance from previous prime (31110030310199) and next prime (31110030310223).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31110030310211 is a prime.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 31110030310211.
It is not a weakly prime, because it can be changed into another prime (31110030310241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15555015155105 + 15555015155106.
It is an arithmetic number, because the mean of its divisors is an integer number (15555015155106).
Almost surely, 231110030310211 is an apocalyptic number.
31110030310211 is a deficient number, since it is larger than the sum of its proper divisors (1).
31110030310211 is an equidigital number, since it uses as much as digits as its factorization.
31110030310211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 31110030310211 its reverse (11201303001113), we get a palindrome (42311333311324).
The spelling of 31110030310211 in words is "thirty-one trillion, one hundred ten billion, thirty million, three hundred ten thousand, two hundred eleven".
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