Base | Representation |
---|---|
bin | 1011100101101110… |
… | …0100101010001001 |
3 | 22000210220211112202 |
4 | 2321123210222021 |
5 | 22332404404001 |
6 | 1232411445545 |
7 | 140044113515 |
oct | 27133445211 |
9 | 8023824482 |
10 | 3111013001 |
11 | 13570a4128 |
12 | 729a568b5 |
13 | 3a76b29c5 |
14 | 217263145 |
15 | 1331c196b |
hex | b96e4a89 |
3111013001 has 2 divisors, whose sum is σ = 3111013002. Its totient is φ = 3111013000.
The previous prime is 3111012997. The next prime is 3111013007. The reversal of 3111013001 is 1003101113.
It is a happy number.
3111013001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2733721225 + 377291776 = 52285^2 + 19424^2 .
It is a cyclic number.
It is not a de Polignac number, because 3111013001 - 22 = 3111012997 is a prime.
It is not a weakly prime, because it can be changed into another prime (3111013007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555506500 + 1555506501.
It is an arithmetic number, because the mean of its divisors is an integer number (1555506501).
Almost surely, 23111013001 is an apocalyptic number.
It is an amenable number.
3111013001 is a deficient number, since it is larger than the sum of its proper divisors (1).
3111013001 is an equidigital number, since it uses as much as digits as its factorization.
3111013001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9, while the sum is 11.
The square root of 3111013001 is about 55776.4556152504. The cubic root of 3111013001 is about 1459.8243675950.
Adding to 3111013001 its reverse (1003101113), we get a palindrome (4114114114).
The spelling of 3111013001 in words is "three billion, one hundred eleven million, thirteen thousand, one".
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