Base | Representation |
---|---|
bin | 100011010111100011110101… |
… | …1010000000111000011001111 |
3 | 1111210111222212101220221101201 |
4 | 1012233013223100013003033 |
5 | 311234040442113120421 |
6 | 3021353545321250331 |
7 | 122346220360301035 |
oct | 10657075320070317 |
9 | 1453458771827351 |
10 | 311101313020111 |
11 | 90143364894a19 |
12 | 2aa856283339a7 |
13 | 10478960381983 |
14 | 56b755357c555 |
15 | 25e76d4665b91 |
hex | 11af1eb4070cf |
311101313020111 has 2 divisors, whose sum is σ = 311101313020112. Its totient is φ = 311101313020110.
The previous prime is 311101313020097. The next prime is 311101313020117. The reversal of 311101313020111 is 111020313101113.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 311101313020111 - 215 = 311101312987343 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (311101313020117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155550656510055 + 155550656510056.
It is an arithmetic number, because the mean of its divisors is an integer number (155550656510056).
Almost surely, 2311101313020111 is an apocalyptic number.
311101313020111 is a deficient number, since it is larger than the sum of its proper divisors (1).
311101313020111 is an equidigital number, since it uses as much as digits as its factorization.
311101313020111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 19.
Adding to 311101313020111 its reverse (111020313101113), we get a palindrome (422121626121224).
The spelling of 311101313020111 in words is "three hundred eleven trillion, one hundred one billion, three hundred thirteen million, twenty thousand, one hundred eleven".
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