Base | Representation |
---|---|
bin | 1001000011011110010… |
… | …00011000010101110101 |
3 | 1002202000020111210212201 |
4 | 10201233020120111311 |
5 | 20044114120110031 |
6 | 354530205544501 |
7 | 31322254221211 |
oct | 4415710302565 |
9 | 1082006453781 |
10 | 311102113141 |
11 | 10aa3503a216 |
12 | 50363575131 |
13 | 2344bc59821 |
14 | 110b37d3941 |
15 | 815c1bdd61 |
hex | 486f218575 |
311102113141 has 2 divisors, whose sum is σ = 311102113142. Its totient is φ = 311102113140.
The previous prime is 311102113087. The next prime is 311102113169. The reversal of 311102113141 is 141311201113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 294083867025 + 17018246116 = 542295^2 + 130454^2 .
It is a cyclic number.
It is not a de Polignac number, because 311102113141 - 211 = 311102111093 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (311102113541) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155551056570 + 155551056571.
It is an arithmetic number, because the mean of its divisors is an integer number (155551056571).
Almost surely, 2311102113141 is an apocalyptic number.
It is an amenable number.
311102113141 is a deficient number, since it is larger than the sum of its proper divisors (1).
311102113141 is an equidigital number, since it uses as much as digits as its factorization.
311102113141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 311102113141 its reverse (141311201113), we get a palindrome (452413314254).
The spelling of 311102113141 in words is "three hundred eleven billion, one hundred two million, one hundred thirteen thousand, one hundred forty-one".
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