Base | Representation |
---|---|
bin | 100011010111100101101100… |
… | …1100111000100001011001101 |
3 | 1111210112101012002201221011111 |
4 | 1012233023121213010023031 |
5 | 311234122134333440203 |
6 | 3021355450213452021 |
7 | 122346421436220313 |
oct | 10657133147041315 |
9 | 1453471162657144 |
10 | 311105312015053 |
11 | 90145027152016 |
12 | 2aa86363641011 |
13 | 10479149a10a7a |
14 | 56b78127100b3 |
15 | 25e786a78d26d |
hex | 11af2d99c42cd |
311105312015053 has 2 divisors, whose sum is σ = 311105312015054. Its totient is φ = 311105312015052.
The previous prime is 311105312015033. The next prime is 311105312015107. The reversal of 311105312015053 is 350510213501113.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 310890315654724 + 214996360329 = 17632082^2 + 463677^2 .
It is a cyclic number.
It is not a de Polignac number, because 311105312015053 - 217 = 311105311883981 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (311105312015033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155552656007526 + 155552656007527.
It is an arithmetic number, because the mean of its divisors is an integer number (155552656007527).
Almost surely, 2311105312015053 is an apocalyptic number.
It is an amenable number.
311105312015053 is a deficient number, since it is larger than the sum of its proper divisors (1).
311105312015053 is an equidigital number, since it uses as much as digits as its factorization.
311105312015053 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6750, while the sum is 31.
Adding to 311105312015053 its reverse (350510213501113), we get a palindrome (661615525516166).
The spelling of 311105312015053 in words is "three hundred eleven trillion, one hundred five billion, three hundred twelve million, fifteen thousand, fifty-three".
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