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31111000231 is a prime number
BaseRepresentation
bin11100111110010111…
…000011000010100111
32222022011211120011211
4130332113003002213
51002203404001411
622143040412251
72150650065403
oct347627030247
988264746154
1031111000231
1112215391a43
126043017087
132c1a5c799c
141711c0c103
15c21434221
hex73e5c30a7

31111000231 has 2 divisors, whose sum is σ = 31111000232. Its totient is φ = 31111000230.

The previous prime is 31111000213. The next prime is 31111000237. The reversal of 31111000231 is 13200011113.

Together with previous prime (31111000213) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 31111000231 - 215 = 31110967463 is a prime.

It is a super-2 number, since 2×311110002312 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31111000237) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15555500115 + 15555500116.

It is an arithmetic number, because the mean of its divisors is an integer number (15555500116).

Almost surely, 231111000231 is an apocalyptic number.

31111000231 is a deficient number, since it is larger than the sum of its proper divisors (1).

31111000231 is an equidigital number, since it uses as much as digits as its factorization.

31111000231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 31111000231 its reverse (13200011113), we get a palindrome (44311011344).

The spelling of 31111000231 in words is "thirty-one billion, one hundred eleven million, two hundred thirty-one", and thus it is an aban number.