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31111031301221 is a prime number
BaseRepresentation
bin1110001001011100110011…
…11110000010010001100101
311002011012000021002200122202
413010232121332002101211
513034210343003114341
6150100113243504245
76360461233544624
oct704563176022145
9132135007080582
1031111031301221
119a05129119a13
1235a5639528085
1314489b07811a1
14797ad39516bb
1538e408e4d79b
hex1c4b99f82465

31111031301221 has 2 divisors, whose sum is σ = 31111031301222. Its totient is φ = 31111031301220.

The previous prime is 31111031301199. The next prime is 31111031301227. The reversal of 31111031301221 is 12210313011113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 29699720565025 + 1411310736196 = 5449745^2 + 1187986^2 .

It is a cyclic number.

It is not a de Polignac number, because 31111031301221 - 242 = 26712984790117 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 31111031301193 and 31111031301202.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31111031301227) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15555515650610 + 15555515650611.

It is an arithmetic number, because the mean of its divisors is an integer number (15555515650611).

Almost surely, 231111031301221 is an apocalyptic number.

It is an amenable number.

31111031301221 is a deficient number, since it is larger than the sum of its proper divisors (1).

31111031301221 is an equidigital number, since it uses as much as digits as its factorization.

31111031301221 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 20.

Adding to 31111031301221 its reverse (12210313011113), we get a palindrome (43321344312334).

The spelling of 31111031301221 in words is "thirty-one trillion, one hundred eleven billion, thirty-one million, three hundred one thousand, two hundred twenty-one".