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31111054504140 = 223513531949386129
BaseRepresentation
bin1110001001011100110110…
…10110100011000011001100
311002011012001212202112002010
413010232123112203003030
513034210414423113030
6150100115433101220
76360461635013622
oct704563326430314
9132135055675063
1031111054504140
119a05140227686
1235a5645257810
1314489b5516420
14797ad6a71512
1538e40aed36b0
hex1c4b9b5a30cc

31111054504140 has 192 divisors, whose sum is σ = 95631118128000. Its totient is φ = 7509738602496.

The previous prime is 31111054504121. The next prime is 31111054504141. The reversal of 31111054504140 is 4140545011113.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a junction number, because it is equal to n+sod(n) for n = 31111054504098 and 31111054504107.

It is not an unprimeable number, because it can be changed into a prime (31111054504141) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 80378596 + ... + 80764724.

It is an arithmetic number, because the mean of its divisors is an integer number (498078740250).

Almost surely, 231111054504140 is an apocalyptic number.

31111054504140 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 31111054504140, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (47815559064000).

31111054504140 is an abundant number, since it is smaller than the sum of its proper divisors (64520063623860).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

31111054504140 is a wasteful number, since it uses less digits than its factorization.

31111054504140 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 388156 (or 388154 counting only the distinct ones).

The product of its (nonzero) digits is 4800, while the sum is 30.

Adding to 31111054504140 its reverse (4140545011113), we get a palindrome (35251599515253).

The spelling of 31111054504140 in words is "thirty-one trillion, one hundred eleven billion, fifty-four million, five hundred four thousand, one hundred forty".