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311113222311149 is a prime number
BaseRepresentation
bin100011010111101001011000…
…1000110011100110011101101
31111210120010121101100121102222
41012233102301012130303231
5311234234334402424044
63021403235150525125
7122350121450510126
oct10657226106346355
91453503541317388
10311113222311149
1190148416320605
122aa879b08067a5
1310479b0a7a694b
1456b7d6310704d
1525e7b7ee698ee
hex11af4b119cced

311113222311149 has 2 divisors, whose sum is σ = 311113222311150. Its totient is φ = 311113222311148.

The previous prime is 311113222311097. The next prime is 311113222311209. The reversal of 311113222311149 is 941113222311113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 264487445824900 + 46625776486249 = 16263070^2 + 6828307^2 .

It is an emirp because it is prime and its reverse (941113222311113) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 311113222311149 - 212 = 311113222307053 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (311113222301149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155556611155574 + 155556611155575.

It is an arithmetic number, because the mean of its divisors is an integer number (155556611155575).

Almost surely, 2311113222311149 is an apocalyptic number.

It is an amenable number.

311113222311149 is a deficient number, since it is larger than the sum of its proper divisors (1).

311113222311149 is an equidigital number, since it uses as much as digits as its factorization.

311113222311149 is an evil number, because the sum of its binary digits is even.

The product of its digits is 7776, while the sum is 35.

The spelling of 311113222311149 in words is "three hundred eleven trillion, one hundred thirteen billion, two hundred twenty-two million, three hundred eleven thousand, one hundred forty-nine".