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3111211213603 is a prime number
BaseRepresentation
bin101101010001100010101…
…000111010001100100011
3102000102120122210021112021
4231101202220322030203
5401433230032313403
610341134245442311
7440530466655403
oct55214250721443
912012518707467
103111211213603
11a9a503691569
12422b82410397
13197502c4933c
14aa824cc8803
1555de2d3e8bd
hex2d462a3a323

3111211213603 has 2 divisors, whose sum is σ = 3111211213604. Its totient is φ = 3111211213602.

The previous prime is 3111211213597. The next prime is 3111211213637. The reversal of 3111211213603 is 3063121121113.

3111211213603 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 3111211213603 - 221 = 3111209116451 is a prime.

It is not a weakly prime, because it can be changed into another prime (3111211213703) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555605606801 + 1555605606802.

It is an arithmetic number, because the mean of its divisors is an integer number (1555605606802).

Almost surely, 23111211213603 is an apocalyptic number.

3111211213603 is a deficient number, since it is larger than the sum of its proper divisors (1).

3111211213603 is an equidigital number, since it uses as much as digits as its factorization.

3111211213603 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 25.

Adding to 3111211213603 its reverse (3063121121113), we get a palindrome (6174332334716).

The spelling of 3111211213603 in words is "three trillion, one hundred eleven billion, two hundred eleven million, two hundred thirteen thousand, six hundred three".