Base | Representation |
---|---|
bin | 1001000011100000100… |
… | …01010110110110010101 |
3 | 1002202001120111201212001 |
4 | 10201300101112312111 |
5 | 20044134014243131 |
6 | 354532131555301 |
7 | 31322605636033 |
oct | 4416021266625 |
9 | 1082046451761 |
10 | 311121243541 |
11 | 10aa44916169 |
12 | 50369a5bb31 |
13 | 23452bc71a4 |
14 | 110b6173553 |
15 | 815dbec261 |
hex | 4870456d95 |
311121243541 has 2 divisors, whose sum is σ = 311121243542. Its totient is φ = 311121243540.
The previous prime is 311121243457. The next prime is 311121243553. The reversal of 311121243541 is 145342121113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 164856300625 + 146264942916 = 406025^2 + 382446^2 .
It is a cyclic number.
It is not a de Polignac number, because 311121243541 - 27 = 311121243413 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (311121243581) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155560621770 + 155560621771.
It is an arithmetic number, because the mean of its divisors is an integer number (155560621771).
Almost surely, 2311121243541 is an apocalyptic number.
It is an amenable number.
311121243541 is a deficient number, since it is larger than the sum of its proper divisors (1).
311121243541 is an equidigital number, since it uses as much as digits as its factorization.
311121243541 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2880, while the sum is 28.
Adding to 311121243541 its reverse (145342121113), we get a palindrome (456463364654).
The spelling of 311121243541 in words is "three hundred eleven billion, one hundred twenty-one million, two hundred forty-three thousand, five hundred forty-one".
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