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31112130000 = 243547148153
BaseRepresentation
bin11100111110011011…
…010110110111010000
32222022020221221221010
4130332123112313100
51002204201130000
622143120530520
72150662512240
oct347633266720
988266857833
1031112130000
1112215a93836
126043480a40
132c1a901ca3
141712023b20
15c215a8d50
hex73e6d6dd0

31112130000 has 200 divisors, whose sum is σ = 114782607808. Its totient is φ = 7111296000.

The previous prime is 31112129989. The next prime is 31112130017. The reversal of 31112130000 is 3121113.

It is a tau number, because it is divible by the number of its divisors (200).

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 135924 + ... + 284076.

Almost surely, 231112130000 is an apocalyptic number.

31112130000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 31112130000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (57391303904).

31112130000 is an abundant number, since it is smaller than the sum of its proper divisors (83670477808).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

31112130000 is a wasteful number, since it uses less digits than its factorization.

31112130000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 148191 (or 148170 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 12.

Adding to 31112130000 its reverse (3121113), we get a palindrome (31115251113).

The spelling of 31112130000 in words is "thirty-one billion, one hundred twelve million, one hundred thirty thousand".