Base | Representation |
---|---|
bin | 1110001001011110110111… |
… | …01001011100100011101111 |
3 | 11002011021212001111221202202 |
4 | 13010233123221130203233 |
5 | 13034220122044400421 |
6 | 150100414445212115 |
7 | 6360530443540055 |
oct | 704573351344357 |
9 | 132137761457682 |
10 | 31112133200111 |
11 | 9a05644110957 |
12 | 35a58a656103b |
13 | 1448b27b48272 |
14 | 797b9a0261d5 |
15 | 38e470a5c10b |
hex | 1c4bdba5c8ef |
31112133200111 has 2 divisors, whose sum is σ = 31112133200112. Its totient is φ = 31112133200110.
The previous prime is 31112133200081. The next prime is 31112133200119. The reversal of 31112133200111 is 11100233121113.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31112133200111 - 26 = 31112133200047 is a prime.
It is a super-2 number, since 2×311121332001112 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31112133200119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15556066600055 + 15556066600056.
It is an arithmetic number, because the mean of its divisors is an integer number (15556066600056).
Almost surely, 231112133200111 is an apocalyptic number.
31112133200111 is a deficient number, since it is larger than the sum of its proper divisors (1).
31112133200111 is an equidigital number, since it uses as much as digits as its factorization.
31112133200111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108, while the sum is 20.
Adding to 31112133200111 its reverse (11100233121113), we get a palindrome (42212366321224).
The spelling of 31112133200111 in words is "thirty-one trillion, one hundred twelve billion, one hundred thirty-three million, two hundred thousand, one hundred eleven".
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