Base | Representation |
---|---|
bin | 1110001001011110111111… |
… | …10000101010101110101111 |
3 | 11002011022000212100121121102 |
4 | 13010233133300222232233 |
5 | 13034220242230431111 |
6 | 150100425352153315 |
7 | 6360532242205616 |
oct | 704573760525657 |
9 | 132138025317542 |
10 | 31112202202031 |
11 | 9a0567a060035 |
12 | 35a590569883b |
13 | 1448b392276c2 |
14 | 797ba526887d |
15 | 38e476b3c13b |
hex | 1c4bdfc2abaf |
31112202202031 has 2 divisors, whose sum is σ = 31112202202032. Its totient is φ = 31112202202030.
The previous prime is 31112202202019. The next prime is 31112202202057. The reversal of 31112202202031 is 13020220221113.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31112202202031 - 222 = 31112198007727 is a prime.
It is a super-2 number, since 2×311122022020312 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 31112202201994 and 31112202202012.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31142202202031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15556101101015 + 15556101101016.
It is an arithmetic number, because the mean of its divisors is an integer number (15556101101016).
Almost surely, 231112202202031 is an apocalyptic number.
31112202202031 is a deficient number, since it is larger than the sum of its proper divisors (1).
31112202202031 is an equidigital number, since it uses as much as digits as its factorization.
31112202202031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 288, while the sum is 20.
Adding to 31112202202031 its reverse (13020220221113), we get a palindrome (44132422423144).
The spelling of 31112202202031 in words is "thirty-one trillion, one hundred twelve billion, two hundred two million, two hundred two thousand, thirty-one".
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