311130000001 has 2 divisors, whose sum is σ = 311130000002. Its totient is φ = 311130000000.

The previous prime is 311129999959. The next prime is 311130000007. The reversal of 311130000001 is 100000031113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 273658719376 + 37471280625 = 523124^2 + 193575^2 .

It is a cyclic number.

It is not a de Polignac number, because 311130000001 - 2¹⁵ = 311129967233 is a prime.

It is not a weakly prime, because it can be changed into another prime (311130000007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155565000000 + 155565000001.

It is an arithmetic number, because the mean of its divisors is an integer number (155565000001).

Almost surely, 2^311130000001 is an apocalyptic number.

It is an amenable number.

311130000001 is a deficient number, since it is larger than the sum of its proper divisors (1).

311130000001 is an equidigital number, since it uses as much as digits as its factorization.

311130000001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9, while the sum is 10.

Adding to 311130000001 its reverse (100000031113), we get a palindrome (411130031114).

The spelling of 311130000001 in words is "three hundred eleven billion, one hundred thirty million, one", and thus it is an aban number.